An airplane travels 710 km at the same time that a Ship travels 110 km. If the rate of the airplane is 20 kph more than 6 times the rate of the ship, what is the rate of each? Solution. let x = rate of ship​

Answer:284 km/hStep-by-step explanation:Given:Distance traveled by the airplane = 710 kmDistance traveled by the ship = 110 kmLet the rate of the ship be x km/hAccording to the problem:Rate of the airplane = 6x + 20 km/hTime taken by the airplane = Time taken by the shipUsing the formula: Time = Distance / RateFor the airplane: 710 / (6x + 20) = tFor the ship: 110 / x = tSince both times are equal:710 / (6x + 20) = 110 / xNow, we can solve this equation to find the rate of the ship (x):710x = 110(6x + 20)710x = 660x + 220050x = 2200x = 44Therefore, the rate of the ship is 44 km/h.Now, we can find the rate of the airplane:Rate of the airplane = 6(44) + 20 = 284 km/hSo, the rate of the ship is 44 km/h, and the rate of the airplane is 284 km/h.

Answered by blaireeeeeee | 2024-09-05