Color Blindness is a sex chromosome linked trait. A woman with normal vision, whose father was color blind, has achild with a man with normal vision.Color Vision alleles: XC = normal color vision allele, X = color blindness alleleGenotypeXCXCXCXCXCXCXCYXCYPhenotypeNormal femaleNormal female - carrier for color blind alleleColor blind femaleNormal maleColor blind maleh) What are the genotypes of the woman and man?i) What proportion of their sons are expected to be color blind? Note: This question is only in regards to thesons. Do not include the daughters in your calculations.j) What proportion of their daughters are expected to be carriers? Note: This question is only in regards tothe daughters. Do not include the sons in your calculations.​

Let's break this down step by step.Given Information:- Color blindness is X-linked (sex-linked), meaning the gene is carried on the X chromosome.- XC represents the normal color vision allele.- X represents the color blindness allele.H) What are the genotypes of the woman and man?1. Woman: - The woman has normal vision but her father was colorblind. - Since color blindness is X-linked, her father must have had the genotype X Y (colorblind male). - The woman must have received one X (colorblind allele) from her father and a normal allele (XC) from her mother. - Therefore, the woman's genotype is XC X (normal vision, carrier for color blindness).2. Man: - The man has normal vision. - His genotype must be XC Y (normal male).I) What proportion of their sons are expected to be color blind?- Sons inherit their X chromosome from their mother and their Y chromosome from their father.- The mother has a 50% chance of passing either her XC (normal) or X (colorblind) allele to her sons.- The father will always pass his Y chromosome (because sons inherit their Y from their father).So, the possible outcomes for sons are:- XC Y (normal vision) or X Y (colorblind).- 50% of the sons are expected to be colorblind.J) What proportion of their daughters are expected to be carriers?- Daughters inherit one X chromosome from their mother and one X chromosome from their father.- The mother has a 50% chance of passing either her XC (normal) or X (colorblind) allele.- The father will always pass his XC (normal) allele to daughters.So, the possible outcomes for daughters are:- XC XC (normal vision) or XC X (normal vision, carrier).- 50% of the daughters are expected to be carriers.

Answered by Blackguard | 2024-09-05