x²+5x+4=09 = 1b = 5C = 4​

Step-by-step explanation:It looks like you have a quadratic equation: \( x^2 + 5x + 4 = 0 \). To find the solutions for this equation, we can use the quadratic formula:\[x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{2a}\]In your equation:- \( a = 1 \)- \( b = 5 \)- \( c = 4 \)Plugging these values into the formula:1. Calculate the discriminant \( b^2 - 4ac \): \[ D = 5^2 - 4(1)(4) = 25 - 16 = 9 \]2. Now apply the quadratic formula: \[ x = \frac{{-5 \pm \sqrt{9}}}{2(1)} = \frac{{-5 \pm 3}}{2} \]3. This gives us two solutions: \[ x_1 = \frac{{-5 + 3}}{2} = \frac{-2}{2} = -1 \] \[ x_2 = \frac{{-5 - 3}}{2} = \frac{-8}{2} = -4 \]So, the solutions to the equation \( x^2 + 5x + 4 = 0 \) are \( x = -1 \) and \( x = -4 \).

Answered by romnickpallon | 2024-09-05