a 0.003kg bullet travels at 300m/s2 how much Kenetic Energy does tt have, pasagot need konaa huhu
Answer (1)
ANSWER: 135JSOLUTION: (If you need) Formula:[tex] \: ke\frac{1}{2} = mv {}^{2} [/tex] [tex] \: \: \: \: \: \: \: \: \: = \frac{1}{2} (0.003kg)(300m s {}^{2} )[/tex][tex] \: \: \: \: \: \: \: \: = \frac{1}{2} (0.003kg)(90000m {}^{2} s {}^{2} )[/tex][tex] \: \: \: \: \: \: \: \: = \frac{1}{2} 270kg.m {}^{2} s {}^{2} [/tex]=135J
