4x²-4+1=0 using quadratic equation using formula​

(2x - 1)(2x - 1)Step-by-step explanation:Quadratic Trinomial (a>1) -> ax² + bx + c = 04x²-4+1 =0 -> multiply a and c4 × 1 = 4 -> find a multiple that sums up to b (-4)4 -> -2 × -2 (-2+-2=-4)*add x to the values and place them beside the it number can be divided to4x²-4+1=04x²-2x -2x+1=0 -> group together by adding parentheses(4x²-2)-(2x-1)=0 -> factor2x(2x-1) -1(2x-1)=0*combine the GCF (outside parentheses) into one parentheses and the factored-out terms (inside parentheses) into another**the factored out terms need to be similar to eachother**Final Ans.: (2x-1)(2x-1)

Answered by astriddejuras10 | 2024-09-04