complete the table[tex] {x}^{2} + 5 \times + 4 = 0[/tex]
Answer (1)
Answer:x²+5x+4=0(x+4)(x+1)=0 x+4=0 | x+1 x=-4 | x=-1Step-by-step explanation:x=-5+-√5²-4(1)(4)/2(1)x=-5+-√25-16/2x=-5+-√9/2x=-5+-3/2x=-5+3/2 or x=-5-3/2x=-2/2 or x=-8/2x=-1 or x=-4
Answer:x²+5x+4=0(x+4)(x+1)=0 x+4=0 | x+1 x=-4 | x=-1Step-by-step explanation:x=-5+-√5²-4(1)(4)/2(1)x=-5+-√25-16/2x=-5+-√9/2x=-5+-3/2x=-5+3/2 or x=-5-3/2x=-2/2 or x=-8/2x=-1 or x=-4
