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In Math / Senior High School | 2024-09-03

How to solve4ײ+8×+3

Asked by barredoj104

Answer (1)

Answer:x=1 and x=-1Step-by-step explanation:completing the square:4x²+8x+34x²/4+8x/4+3/4x²+2x=-3/4x²+2x+1=-3/4+1/1 (x+1)²=-8/4√(x+1)²=√-1/2x=-1+√-1/2Using quadratic formulax= -(8)+-√8²-4(4)(3)/2(4)x=-8+-√64-48/8x=-8+-√16/8x=-8+-4/8x=-8-4/4 or x=-8+4/4x=4/4 and x=-4/4x=1 and x=-1

Answered by Kiminokorimbuin | 2024-09-03