x219x+18= 0wing quadratica=1be918x = - b ± √√62-4ac29-(-9) ± √(-9)2-4(1)(18)2(1)9tgl72*=21X=XE3*=9+3ZN122x= 6x=9-326N3

Question

x219x+18= 0wing quadratica=1be918x = - b ± √√62-4ac29-(-9) ± √(-9)2-4(1)(18)2(1)9tgl72*=21X=XE3*=9+3ZN122x= 6x=9-326N3​

rumika72h · Answer

= 300 po kasi ayun po Ung sagot

x219x+18= 0wing quadratica=1be918x = - b ± √√62-4ac29-(-9) ± √(-9)2-4(1)(18)2(1)9tgl72=21X=XE3=9+3ZN122x= 6x=9-326N3