how to solve this 9 2/5 divided by 1 3/10 in 6grade​

Step-by-step explanation:Here's how to solve 9 2/5 divided by 1 3/10 in a way that's easy for a 6th grader to understand: 1. Turn the mixed numbers into improper fractions: - 9 2/5: (9 * 5) + 2 = 47. Keep the denominator: 47/5- 1 3/10: (1 * 10) + 3 = 13. Keep the denominator: 13/10 2. Remember that dividing by a fraction is the same as multiplying by its reciprocal: - The reciprocal of 13/10 is 10/13. 3. Multiply the fractions: - (47/5) * (10/13) 4. Simplify: - You can cross-cancel: 10 and 5 both have a common factor of 5.- (47/1) * (2/13) = 94/13 5. Convert the improper fraction back to a mixed number: - 94 divided by 13 is 7 with a remainder of 3.- So, the answer is 7 3/13

Answered by celestinerhai | 2024-09-03

Answer:9 25÷ 1 310 = ?Convert any mixed numbers to fractions:9 25= 4751 310= 1310Division of fractions is equivalent to multiplication by the reciprocal of the second fraction:475÷ 1310= 475× 1013Once rearranged, multiply all of the numerators by each other. Do the same with the denominators and form a new fraction with these values:47 × 105 × 13= 47065The Greatest Common Factor (GCF) of 470 and 65 is 5. The result can be simplified by dividing both the numerator and denominator by 5.47065= 470 ÷ 565 ÷ 5= 941394 ÷ 13 = 7R3, therefore:9413= 7 313The result is:9 25÷ 1 310= 7 313

Answered by justinezalan | 2024-09-03