show your solution by using the continuous division method to find the GCF of the following sets of numbers 1. 25,30,42 2. 24,36,48 3. 18,12,16 4. 39,52,91 5. 56,72,80,90 6. 68,102,136,153 7. 72 and 90 8. 432 and 522 9. 132,176 and 264 10. 198, 242 and 330
Answer (1)
Answer:To find the Greatest Common Factor (GCF) of the given sets of numbers using the continuous division method, we will perform a series of division operations until we reach a common divisor. Let's start with each set of numbers: Set 1: 25, 30, 42 - GCF(25, 30) = 5- GCF(5, 42) = 1- Therefore, the GCF of 25, 30, and 42 is 1. Set 2: 24, 36, 48 - GCF(24, 36) = 12- GCF(12, 48) = 12- Therefore, the GCF of 24, 36, and 48 is 12. Set 3: 18, 12, 16 - GCF(18, 12) = 6- GCF(6, 16) = 2- Therefore, the GCF of 18, 12, and 16 is 2. Set 4: 39, 52, 91 - GCF(39, 52) = 13- GCF(13, 91) = 13- Therefore, the GCF of 39, 52, and 91 is 13. Set 5: 56, 72, 80, 90 - GCF(56, 72) = 8- GCF(8, 80) = 8- GCF(8, 90) = 2- Therefore, the GCF of 56, 72, 80, and 90 is 2. Set 6: 68, 102, 136, 153 - GCF(68, 102) = 34- GCF(34, 136) = 34- GCF(34, 153) = 17- Therefore, the GCF of 68, 102, 136, and 153 is 17. Set 7: 72, 90 - GCF(72, 90) = 18- Therefore, the GCF of 72 and 90 is 18. Set 8: 432, 522 - GCF(432, 522) = 6- Therefore, the GCF of 432 and 522 is 6. Set 9: 132, 176, 264 - GCF(132, 176) = 44- GCF(44, 264) = 44- Therefore, the GCF of 132, 176, and 264 is 44. Set 10: 198, 242, 330 - GCF(198, 242) = 22- GCF(22, 330) = 22- Therefore, the GCF of 198, 242, and 330 is 22. These are the GCFs of the given sets of numbers as determined using the continuous division method.
