Solving Quadratic equation by:completing the squared x²+3x-18=0
Answer (1)
Answer:[tex] {x}^{2} + 3x - 18 = 0 \\ \\ {x}^{2} + 3x - 18 = 0 \\ {x}^{2} + 3x = 18 \\ \\ = {( \frac{b}{2} )}^{2} \\ = {( \frac{3}{2}) }^{2} \\ = \frac{ {3}^{2} }{ {2}^{2} } \\ = \frac{9}{4} \\ \\ {x}^{2} + 3x + \frac{9}{4} = 18 + \frac{9}{4} \\ {x}^{2} + 3x + \frac{9}{4} = \frac{81}{4} \\ {(x + \frac{3}{2}) }^{2} = \frac{81}{4} \\ \sqrt{ {(x + \frac{3}{2}) }^{2} } = \sqrt{ \frac{81}{4} } \\ x + \frac{3}{2} = ± \frac{9}{2} \\ x = - \frac{3}{2} ± \frac{9}{2} \\ \\ x_{1} = - \frac{3}{2} + \frac{9}{2} \: \: \: \: \: \: \: \: \: \: \: \: \: x_{2} = - \frac{3}{2} - \frac{9}{2} \\ x_{1} = \frac{6}{2} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x_{2} = - \frac{12}{2} \\ x_{1} = 3 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: x_{2} = - 6[/tex]Step-by-step explanation:isang brainliest naman jan. baka naman. salamat po. have a nice day. sana makatulong..
