Answer:The sum of the first six terms of the arithmetic sequence is 78.Step-by-step explanation:Given:a1 = 3a3 = 11d = 11n = 6Required:S6 = ?Solution:Solve for a6.a6 = a1 + (n - 1)da6 = 3 + (6 - 1)(4)a6 = 3 + 5(4)a6 = 3 + 20a6 = 23Solve for S6.Sn = n/2 [2a + (n - 1)d]S6 = 6/2 [2(3) + (6 - 1)(4)]S6 = 3[6 + 5(4)]S6 = 3[6 + 20]S6 = 3(26)S6 = 78