the first 14 terms of 6+9+12+... ​

Answer:The first 14 terms of the series 6 + 9 + 12 + ... are:6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45.Step-by-step explanation:To find the first 14 terms of the series 6 + 9 + 12 + ..., we need to identify the pattern of the series and then calculate the terms. Given series: 6 + 9 + 12 + ... Pattern:The series is an arithmetic progression where each term is obtained by adding 3 to the previous term. General form of an arithmetic progression:a_n = a_1 + (n-1)d Where: - a_n is the nth term of the series,- a_1 is the first term of the series,- n is the term number,- d is the common difference between the terms. In this series: - a_1 = 6 (first term)- d = 3 (common difference) Calculating the terms: 1. a_2 = 6 + 3 = 92. a_3 = 9 + 3 = 123. a_4 = 12 + 3 = 154. a_5 = 15 + 3 = 185. a_6 = 18 + 3 = 216. a_7 = 21 + 3 = 247. a_8 = 24 + 3 = 278. a_9 = 27 + 3 = 309. a_{10} = 30 + 3 = 3310. a_{11} = 33 + 3 = 3611. a_{12} = 36 + 3 = 3912. a_{13} = 39 + 3 = 4213. a_{14} = 42 + 3 = 45 Therefore, the first 14 terms of the series 6 + 9 + 12 + ... are:6, 9, 12, 15, 18, 21, 24, 27, 30, 33, 36, 39, 42, 45.

Answered by llehcim72 | 2024-09-01