A huge stone is pushed with 30 N of force. If there is only 5N of friction and the stone’s
mass is 88 kg. What is the acceleration of the table?

Answer:The problem asks for the acceleration of the table, but the table is not moving in the problem. Therefore, the acceleration of the table is 0 m/s^2.The problem seems to be asking for the acceleration of the stone. To find the acceleration of the stone, we can use Newton's second law:Fnet = mawhere Fnet is the net force acting on the stone, m is the mass of the stone, and a is the acceleration of the stone.In this case, the net force acting on the stone is the applied force minus the frictional force:Fnet = 30 N - 5 N = 25 NSubstituting this into Newton's second law, we get:25 N = 88 kg * aSolving for a, we get:a = 25 N / 88 kg ≈ 0.284 m/s^2Therefore, the acceleration of the stone is approximately 0.284 m/s^2.

Answered by ortegatristhan | 2024-09-02