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In Math / Junior High School | 2024-09-01

1. Find the 42nd term of the arithmetic sequence 5, 10, 15,...​

Asked by wenminguito056

Answer (2)

Step-by-step explanation:the process of finding the factors of an expression

Answered by jasminallequir31 | 2024-09-01

SOLUTION:Step 1: List the given values.[tex]\begin{aligned} & n = 42 \\ & a_1 = 5 \\ & a_2 = 10 \\ & a_3 = 15 \end{aligned}[/tex]Step 2: Find the common difference.[tex]\begin{aligned} d & = a_2 - a_1 = a_3 - a_2 \\ & = 10 - 5 = 15 - 10 \\ d & = 5 = 5 \end{aligned}[/tex]Step 3: Solve for the 42nd term of an arithmetic sequence.[tex]\begin{aligned} a_n & = a_1 + (n - 1)d \\ a_{42} & = 5 + (42 - 1)(5) \\ & = 5 + 41(5) \\ & = 5 + 205 \\ & = \boxed{210} \end{aligned}[/tex]Hence, the 42nd term of an arithmetic sequence is 210.

Answered by GreatRedSpot | 2024-09-01