the 4th term of an arithmetic sequence is 20 and the 7th term is 32 determine the common difference of the sequence
Answer (2)
given[tex]a_{4} = a_{1} + 3d = 20[/tex][tex]a_{7} = a_{1} + 6d = 32[/tex]requiredcommon difference (d)solution (subtract eq 1 from eq 2)[tex](a_{1} + 6d) - (a_{1} + 3d) = 32 - 20[/tex][tex]3d = 12[/tex][tex]d = \frac{12}{3} = 4[/tex]answerd = 4
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